Examine whether the following equation is qua | vedclass

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Question

(B) Given equation: $(3x + 1)(3x + 2) = (9x - 1)(x + 1)$Expanding both sides:$9x^2 + 6x + 3x + 2 = 9x^2 + 9x - x - 1$$9x^2 + 9x + 2 = 9x^2 + 8x - 1$Su

Vedclass · Accepted Answer

No,it is not a quadratic equation.

Vedclass · Answer

(B) Given equation: $(3x + 1)(3x + 2) = (9x - 1)(x + 1)$Expanding both sides:$9x^2 + 6x + 3x + 2 = 9x^2 + 9x - x - 1$$9x^2 + 9x + 2 = 9x^2 + 8x - 1$Subtracting $(9x^2 + 8x - 1)$ from both sides:$9x^2 - 9x^2 + 9x - 8x + 2 + 1 = 0$$x + 3 = 0$The degree of the resulting polynomial $p(x) = x + 3$ is $1$.Since the degree of the equation is not $2$,it is not a quadratic equation. It is a linear equation.

Examine whether the following equation is quadratic or not: $(3x + 1)(3x + 2) = (9x - 1)(x + 1)$

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